已知函数f(x)=x3-x,g(x)=x2+a,曲线y=f(x)在点(x1,f(x1))处的切线也是曲线y=g(x)的切线.
(1)若x1=-1,求a;
(2)求a的取值范围.
已知函数f(x)=x3-x,g(x)=x2+a,曲线y=f(x)在点(x1,f(x1))处的切线也是曲线y=g(x)的切线.
(1)若x1=-1,求a;
(2)求a的取值范围.
(1)由题意知,f(-1)=-1-(-1)=0,f' (x)=3x2-1,f' (-1)=3-1=2,则y=f(x)在点(-1,0)处的切线方程为y=2(x+1),即y=2x+2,设该切线与g(x)切于点(x2,g(x2)),g' (x)=2x,则g' (x2)=2x2=2,解得x2=1,则g(1)=1+a=2+2,解得a=3;(2)f' (x)=3x2-1,则y=f(x)在点(x1,f(x1))处的切线方程为y-(x13-x1 )=(3x12-1)(x-x1),整理得y=(3x12-1)x-2x13,设该切线与g(x)切于点(x2,g(x2)),g' (x)=2x,则g' (x2)=2x...
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