若A+B+C=180°,证:
sin(B+2C)+sin(C+2A)+sin(A+2B)=4 sin1/2(B-C)∙sin1/2 (C-A)∙sin1/2(A-B)
若A+B+C=180°,证:
sin(B+2C)+sin(C+2A)+sin(A+2B)=4 sin1/2(B-C)∙sin1/2 (C-A)∙sin1/2(A-B)
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