设u(x,y)=ex(xsiny+ycosy),求出解析函数f(z)=u(x,y)+iv(x,y).
设u(x,y)=ex(xsiny+ycosy),求出解析函数f(z)=u(x,y)+iv(x,y).
.∂u/∂x=∂v/∂y=ex (xcosy+cosy-ysiny),∂u/∂y=-∂v/∂x=ex (xsiny+ycosy-siny),du=ex [(x+1)cosy-ysiny]dx-ex [(x+1)siny+ycosy]dy.u(x,y)=ex [(x+1)cosy-ysiny]dx-ex [(x+1)siny+ycosy]dy=ex [(x+1)cosy0-...
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